JEE MathsDifferential EquationsVisual Solution
Visual SolutionEasy
Question
The order and degree of the differential equation (d2ydx2)3=(1+(dydx)2)5/2\left(\frac{d^2y}{dx^2}\right)^3 = \left(1 + \left(\frac{dy}{dx}\right)^2\right)^{5/2} are respectively:
(A)22 and 33
(B)22 and 66
(C)22 and 55
(D)33 and 22
Solution Path
Order = 2 (highest derivative). Square both sides to remove fractional exponent, degree = 6.
01Question Setup
1/4
Find the order and degree of (d2ydx2)3=(1+(dydx)2)5/2\left(\frac{d^2y}{dx^2}\right)^3 = \left(1 + \left(\frac{dy}{dx}\right)^2\right)^{5/2}.
Order =  ?= \;?, Degree =  ?= \;?
02Identify Order
2/4
Highest derivative is d2ydx2\frac{d^2y}{dx^2}, so order =2= 2. But the RHS has a fractional exponent 5/25/2 - degree is not defined until we remove it.
Order =2= 2
03Remove Fractional ExponentKEY INSIGHT
3/4
Square both sides: (d2ydx2)6=(1+(dydx)2)5\left(\frac{d^2y}{dx^2}\right)^6 = \left(1 + \left(\frac{dy}{dx}\right)^2\right)^5. Now degree =6= 6 (power of highest order derivative).
Degree =6= 6
04Final Answer
4/4
Order =2= 2, Degree =6= 6. Sum =8= 8.
Order 2, Degree 6\boxed{\text{Order } 2, \text{ Degree } 6}
Concepts from this question1 concepts unlocked

Formation by Elimination of Constants

STANDARD

Differentiate the given family of curves n times and eliminate all n arbitrary constants to obtain the differential equation

n arbitrary constants    n differentiations to eliminaten \text{ arbitrary constants} \implies n \text{ differentiations to eliminate}

Tested frequently in JEE for finding the order of a differential equation and connecting curve families to their ODEs

Order and degree problemsFamily of curvesEnvelope problems
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