Visual SolutionPYQ 2024 · Jan Shift 2Standard
Question
If 0π/3cos4xdx=aπ+b3\int_0^{\pi/3} \cos^4 x \, dx = a\pi + b\sqrt{3}, where aa and bb are rational numbers, then 9a+8b9a + 8b is equal to:
(A)22
(B)11
(C)33
(D)32\frac{3}{2}
Solution Path
Power reduction: cos4x=38+cos2x2+cos4x8\cos^4 x = \frac{3}{8} + \frac{\cos 2x}{2} + \frac{\cos 4x}{8}. Integrate to get a=18,b=764a=\frac{1}{8}, b=\frac{7}{64}. Answer: 9a+8b=29a+8b=2.
01Question Setup
1/4
0π/3cos4xdx=aπ+b3\int_0^{\pi/3} \cos^4 x\, dx = a\pi + b\sqrt{3}. Find 9a+8b9a + 8b.
9a+8b=  ?9a + 8b = \;?
02Power Reduction
2/4
cos4x=38+cos2x2+cos4x8\cos^4 x = \frac{3}{8} + \frac{\cos 2x}{2} + \frac{\cos 4x}{8} using double angle identities.
cos4x=38+\cos^4 x = \frac{3}{8} + \cdots
03EvaluateKEY INSIGHT
3/4
Integrating: π8+7364\frac{\pi}{8} + \frac{7\sqrt{3}}{64}. So a=18,b=764a = \frac{1}{8}, b = \frac{7}{64}. Then 9a+8b=29a + 8b = 2.
9a+8b=29a + 8b = 2
04Final Answer
4/4
9a+8b=29a + 8b = 2.
2\boxed{2}
Concepts from this question2 concepts unlocked

Substitution Method

EASY

Replace a composite expression with a single variable to simplify the integrand

f(g(x))g(x)dx=f(t)dt,t=g(x)\int f(g(x))\,g'(x)\,dx = \int f(t)\,dt, \quad t = g(x)

Transforms complex integrands into standard forms that can be integrated directly

Trigonometric integralsRational functionsPower rule integrals
Practice (22 Qs) →

Odd/Even Function Symmetry

EASY

For symmetric limits, odd functions integrate to zero and even functions double

aaf(x)dx={0f(x)=f(x)20af(x)dxf(x)=f(x)\int_{-a}^{a} f(x)\,dx = \begin{cases} 0 & f(-x) = -f(x) \\ 2\int_0^a f(x)\,dx & f(-x) = f(x) \end{cases}

Saves computation by detecting when an integral vanishes or can be simplified

Definite integralsTrigonometric integrals
Practice (8 Qs) →