Visual SolutionStandard
Question
lim⁡x→0ex−esin⁡xx−sin⁡x\displaystyle\lim_{x \to 0} \frac{e^x - e^{\sin x}}{x - \sin x} is equal to:
(A)ee
(B)00
(C)11
(D)−1-1
Solution Path
Factor esin⁡xe^{\sin x} from numerator, apply standard limit lim⁡(et−1)/t=1\lim (e^t-1)/t = 1 with t=x−sin⁡xt = x - \sin x. Answer: 1.
01Question Setup
1/4
Evaluate lim⁡x→0ex−esin⁡xx−sin⁡x\displaystyle\lim_{x \to 0} \frac{e^x - e^{\sin x}}{x - \sin x}. Both numerator and denominator approach 0.
00\frac{0}{0} form
02Factor the Numerator
2/4
Factor out esin⁡xe^{\sin x}: esin⁡x(ex−sin⁡x−1)x−sin⁡x\frac{e^{\sin x}(e^{x - \sin x} - 1)}{x - \sin x}. Now we have a standard limit form.
esin⁡x⋅ex−sin⁡x−1x−sin⁡xe^{\sin x} \cdot \frac{e^{x-\sin x} - 1}{x - \sin x}
03Standard LimitKEY INSIGHT
3/4
Let t=x−sin⁡x→0t = x - \sin x \to 0. Use lim⁡t→0et−1t=1\displaystyle\lim_{t \to 0} \frac{e^t - 1}{t} = 1. Also esin⁡x→e0=1e^{\sin x} \to e^0 = 1. So the limit =1⋅1=1= 1 \cdot 1 = 1.
lim⁡et−1t=1\displaystyle\lim \frac{e^t - 1}{t} = 1
04Final Answer
4/4
The limit equals 1. Answer is (C).
1\boxed{1}
Concepts from this question2 concepts unlocked
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L'Hopital's Rule Application

STANDARD

When a limit yields 0/0 or infinity/infinity, differentiate the numerator and denominator separately and re-evaluate the limit

00 or ∞∞  ⟹  lim⁡x→af(x)g(x)=lim⁡x→af′(x)g′(x)\frac{0}{0} \text{ or } \frac{\infty}{\infty} \implies \lim_{x \to a} \frac{f(x)}{g(x)} = \lim_{x \to a} \frac{f'(x)}{g'(x)}

Provides a systematic fallback when standard forms and algebraic tricks fail to resolve indeterminate limits

Indeterminate form limitsExponential limitsLogarithmic limits
Practice (10 Qs) →

Standard Limit Forms

EASY

The seven fundamental limits that serve as building blocks for evaluating all other limits: sin x/x, tan x/x, (1+1/x)^x, (e^x-1)/x, (a^x-1)/x, log(1+x)/x, and (1+x)^(1/x)

lim⁡x→0sin⁡xx=1,lim⁡x→0ex−1x=1,lim⁡x→∞(1+1x)x=e\lim_{x \to 0} \frac{\sin x}{x} = 1, \quad \lim_{x \to 0} \frac{e^x - 1}{x} = 1, \quad \lim_{x \to \infty} \left(1 + \frac{1}{x}\right)^x = e

Most JEE limit problems reduce to one of these standard forms after algebraic manipulation or substitution

Direct substitution limitsTrigonometric limitsExponential limits
Practice (14 Qs) →