Visual SolutionPYQ 2024 · Jan 27 Shift 1Easy
Question
Consider the matrix f(x)=[cosxsinx0sinxcosx0001]f(x) = \begin{bmatrix} \cos x & -\sin x & 0 \\ \sin x & \cos x & 0 \\ 0 & 0 & 1 \end{bmatrix}.\n\nStatement I: f(x)f(-x) is the inverse of f(x)f(x).\nStatement II: f(x)f(y)=f(x+y)f(x) \cdot f(y) = f(x + y).\n\nWhich of the following is correct?
(A)Statement I is false but Statement II is true
(B)Both Statement I and Statement II are false
(C)Statement I is true but Statement II is false
(D)Both Statement I and Statement II are true
Solution Path
f(x)f(x) is a rotation matrix. f(x)=f(x)1f(-x) = f(x)^{-1} via cos2+sin2=1\cos^2+\sin^2=1. f(x)f(y)=f(x+y)f(x)f(y) = f(x+y) via angle addition. Both true.
01Question Setup
1/4
Rotation matrix f(x)f(x) is 3×33 \times 3 with cosx,sinx\cos x, -\sin x in the top-left block. Check two statements about its properties.
Check Statements I and II
02Statement I: Inverse
2/4
Compute f(x)f(x)f(x) \cdot f(-x). Using cos2x+sin2x=1\cos^2 x + \sin^2 x = 1, the product equals the identity matrix II.
f(x)f(x)=I    f(x)=f(x)1f(x) \cdot f(-x) = I \implies f(-x) = f(x)^{-1} - TRUE
03Statement II: CompositionKEY INSIGHT
3/4
Rotation composition = angle addition. By the angle addition formulas, f(x)f(y)=f(x+y)f(x) \cdot f(y) = f(x+y).
f(x)f(y)=f(x+y)f(x) \cdot f(y) = f(x+y) - TRUE
04Final Answer
4/4
Both statements are true. f(x)f(x) is an orthogonal rotation matrix.
Both true\boxed{\text{Both true}} - Answer (D)
Concepts from this question1 concepts unlocked

Eigenvalues, Trace & Determinant

EASY

For a square matrix A: tr(A) = sum of eigenvalues, det(A) = product of eigenvalues.

tr(A)=λi,A=λi\text{tr}(A) = \sum \lambda_i, \quad |A| = \prod \lambda_i

Converts matrix questions into simple algebra on eigenvalues. Saves you from computing A² explicitly.

Trace problemsDeterminant shortcutsCharacteristic equation
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