Visual SolutionPYQ 2024 · Apr 6 Shift 1Standard
Question
The number of triangles whose vertices are at the vertices of a regular octagon but none of whose sides is a side of the octagon is
(A)4848
(B)5656
(C)2424
(D)1616
Solution Path
Total =8C3=56= {}^{8}C_{3} = 56. With at least 1 octagon side: 32+8=4032 + 8 = 40. No octagon side =5640=16= 56 - 40 = 16.
01Question Setup
1/4
Regular octagon with vertices labeled 11 to 88. Count triangles with NO side coinciding with an octagon side.
Count triangles with no octagon side
02Count Cases
2/4
Total triangles: 8C3=56{}^{8}C_{3} = 56. Triangles with exactly 1 octagon side: 8×4=328 \times 4 = 32. Triangles with exactly 2 octagon sides (3 consecutive): 88.
8C3=56{}^{8}C_{3} = 56, with 1 side: 3232, with 2 sides: 88
03SubtractKEY INSIGHT
3/4
Triangles with at least 1 octagon side =32+8=40= 32 + 8 = 40. Subtract from total: 5640=1656 - 40 = 16.
No octagon side =5640=16= 56 - 40 = 16
04Final Answer
4/4
Complementary counting: total minus those with at least one octagon side.
16\boxed{16} - Answer (D)
Concepts from this question1 concepts unlocked

Complementary Counting

STANDARD

Count what you don't want and subtract from total: desired = total - undesired

A=UAc|A| = |U| - |A^c|

When the constraint is complex, counting the complement is often far simpler. Saves 3-4 minutes on hard P&C problems.

At-least-one problemsDerangementsRestriction problems
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