Wrong formula for shortest distance between skew lines
Very CommonFORMULA
Students either use the wrong vectors in the scalar triple product or confuse the shortest distance formula with the distance from a point to a line.
Why: The formula involves three vector operations (subtraction, cross product, dot product) and students mix up which vectors go where.
WRONG:Computing ∣a1×a2∣∣(a1−a2)⋅(b1×b2)∣ or using direction vectors in the numerator instead of the position vector difference.
RIGHT:Lines r=a1+tb1 and r=a2+sb2. Distance =∣b1×b2∣∣(a2−a1)⋅(b1×b2)∣. Numerator uses position vectors; denominator uses direction vectors.
Students mix up when to use the dot product being zero (perpendicular) versus the cross product being zero (parallel).
Why: The conditions for parallel planes (normals are parallel) and perpendicular planes (normals are perpendicular) are easily confused, especially under time pressure.
WRONG:Setting a1a2+b1b2+c1c2=0 for parallel planes, when this is actually the condition for perpendicular planes.
The angle between a line and a plane uses sinθ, while the angle between two planes uses cosθ. Students apply the wrong trig function.
Why: Both formulas look similar (dot product of direction vectors divided by magnitudes), but one uses cos and the other uses sin.
WRONG:Using cosθ=∣b∣∣n∣∣b⋅n∣ for the angle between a line and a plane, when it should be sinθ.
RIGHT:Line-plane angle: sinθ=∣b∣∣n∣∣b⋅n∣. Plane-plane angle: cosθ=∣n1∣∣n2∣∣n1⋅n2∣. Remember: line-plane angle is the complement of line-normal angle.