JEE Maths›Limits, Continuity & Differentiability›Visual Solutions

Visual Solutions

3 step-by-step animated solutions for Limits, Continuity & Differentiability. Each solution breaks the problem into visual clips with key insights.

Standard4 steps
The value of lim⁡x→0(1+x)1/x−ex\displaystyle\lim_{x \to 0} \frac{(1 + x)^{1/x} - e}{x} is:
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Standard4 steps
The value of lim⁡x→0(sin⁡xx)1/x2\displaystyle\lim_{x \to 0} \left(\frac{\sin x}{x}\right)^{1/x^2} is:
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Standard4 steps
lim⁡x→0ex−esin⁡xx−sin⁡x\displaystyle\lim_{x \to 0} \frac{e^x - e^{\sin x}}{x - \sin x} is equal to:
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